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Modelio 4.0.0 released (07 Nov 2019)
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[Solved] Copy of Element through command
5 years 6 months ago - 5 years 6 months ago #4300 by kurales
Hi,
I would like to create a command to copy an element (component) in diagram, but can't understand, how can I get the root Element for the method modelFactory.createComponent("Component", (NameSpace) parent, s);
where "parent" should be this root element. I know, that when I implement IBoxTool-Interface there is an diagramHandle, for which I can get .getDiagram().getOrigin() for my purpose, but when I create a command where I extend DefaultModuleCommandHandler, I can't understand what to do.
Can somebody help me?
I would like to create a command to copy an element (component) in diagram, but can't understand, how can I get the root Element for the method modelFactory.createComponent("Component", (NameSpace) parent, s);
where "parent" should be this root element. I know, that when I implement IBoxTool-Interface there is an diagramHandle, for which I can get .getDiagram().getOrigin() for my purpose, but when I create a command where I extend DefaultModuleCommandHandler, I can't understand what to do.
Can somebody help me?
Last Edit: 5 years 6 months ago by kurales.
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5 years 6 months ago #4301 by kurales
I have found, how can I get the root Element:
MObject root = Modelio.getInstance().getModelingSession().getModel().getModelRoots().get(0);
Package rootPackage = ((Project) root).getModel();
and then
modelFactory.createComponent("Component", rootPackage, s);
But the created Element appears in the project-tree and not on the diagram. Is there something like
diagramHandle.unmask(newElement, rect.x, rect.y);
in this case?
MObject root = Modelio.getInstance().getModelingSession().getModel().getModelRoots().get(0);
Package rootPackage = ((Project) root).getModel();
and then
modelFactory.createComponent("Component", rootPackage, s);
But the created Element appears in the project-tree and not on the diagram. Is there something like
diagramHandle.unmask(newElement, rect.x, rect.y);
in this case?
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5 years 6 months ago #4302 by kurales
I did it too:
There is now only one question: how can I get bounds of the element?
IDiagramService diagramServices = Modelio.getInstance().getDiagramService();for (StaticDiagram diagram : session.findByClass(StaticDiagram.class)) {
// if diagram context is root
if (rootPackage.equals(diagram.getOrigin())) {
// Get a IDiagramHandle for content manipulation.
IDiagramHandle dh = diagramServices.getDiagramHandle(diagram);
dh.unmask(createdElement, 0, 0);
// Save all diagram modifications
dh.save();
// Close the handle now it is no longer used
dh.close();
}
}There is now only one question: how can I get bounds of the element?
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5 years 6 months ago #4303 by kurales
For my previous question:
And the last question: how can I get the list of stereotypes (or only one) of my host-element? I see only functions, which require the name of Stereotype, but this name I would like to get.
IDiagramNode dg = (IDiagramNode) dh.getDiagramGraphics(el).get(0);
dh.unmask(createdElement, dg.getBounds().x+100, dg.getBounds().y);And the last question: how can I get the list of stereotypes (or only one) of my host-element? I see only functions, which require the name of Stereotype, but this name I would like to get.
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5 years 6 months ago #4304 by chm
Hi kurales,
to get names of all stereotypes applied on your model element, try this:
Hope this helps,
chm
to get names of all stereotypes applied on your model element, try this:
List<String> stereotypeNames = new ArrayList<>();
for (Stereotype s : el.getExtension()) {
stereotypeNames.add(s.getName());
}Hope this helps,
chm
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5 years 6 months ago #4305 by kurales
Hi chm,
Thank you very much, it works!
Thank you very much, it works!
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